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(a^2-11a+30)/(a-6)=0
Domain of the equation: (a-6)!=0We multiply all the terms by the denominator
We move all terms containing a to the left, all other terms to the right
a!=6
a∈R
(a^2-11a+30)=0
We get rid of parentheses
a^2-11a+30=0
a = 1; b = -11; c = +30;
Δ = b2-4ac
Δ = -112-4·1·30
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*1}=\frac{10}{2} =5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*1}=\frac{12}{2} =6 $
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